Solve for x: 6⋅x + 2 = 5⋅x -- 1

Solve for x: 6⋅x + 2 = 5⋅x -- 1

• A. 3.1
• B. --3.0
• C. --2.2
• D. --4.1

Answer: (B)

To solve the equation \(6 \cdot x + 2 = 5 \cdot x - 1\), we start by isolating the variable \(x\). First, let's move the terms involving \(x\) to one side of the equation and the constant terms to the other side. We can do this by subtracting \(5 \cdot x\) from both sides. This gives us: \[ 6 \cdot x - 5 \cdot x + 2 = -1 \] This simplifies to: \[ x + 2 = -1 \] Next, we isolate \(x\) by subtracting 2 from both sides: \[ x = -1 - 2 \] This simplifies to: \[ x = -3 \] In decimal form, this can also be represented as \(-3.0\). Therefore, this solution matches the correct choice as it states \(x = -3.0\). In summary, the process involves combining like terms and isolating the variable to arrive at the solution. This method ensures that the correct answer is found, allowing for careful verification throughout the steps.

To solve the equation (6 \cdot x + 2 = 5 \cdot x - 1), we start by isolating the variable (x).

First, let's move the terms involving (x) to one side of the equation and the constant terms to the other side. We can do this by subtracting (5 \cdot x) from both sides. This gives us:

[ 6 \cdot x - 5 \cdot x + 2 = -1 ]

This simplifies to:

[ x + 2 = -1 ]

Next, we isolate (x) by subtracting 2 from both sides:

[ x = -1 - 2 ]

This simplifies to:

[ x = -3 ]

In decimal form, this can also be represented as (-3.0). Therefore, this solution matches the correct choice as it states (x = -3.0).

In summary, the process involves combining like terms and isolating the variable to arrive at the solution. This method ensures that the correct answer is found, allowing for careful verification throughout the steps.